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SHEAR STRENGTH OF SOIL (MOHR–COULOMB THEORY) #SOIL MECHANICS

SOIL MECHANICS – CHAPTER 8

SHEAR STRENGTH OF SOIL (MOHR–COULOMB THEORY)

(SSC JE | RRB JE | OSSC JE – VERY HIGH WEIGHTAGE & NUMERICAL-HEAVY)

👉 3–5 questions every exam
👉 Pure scoring chapter if formulas + concepts are clear
👉 Direct numericals + tricky conceptual MCQs

4

🔹 1. ONE-PAGE PRECISE ONE-LINER NOTES (EXAM FOCUSED)

🔸 Shear Strength

🔸 Mohr–Coulomb Failure Theory (MOST IMPORTANT)

Where:

🔸 Components of Shear Strength

1️⃣ Cohesion (c) → electro-chemical bonding
2️⃣ Friction (φ) → interlocking & roughness

🔸 Effective Stress Principle

🔸 Drained vs Undrained Conditions

Condition Pore pressure Parameters
Drained Dissipated c′, φ′
Undrained Not dissipated cu (φ = 0)

🔸 Special Soil Conditions (EXAM FAVOURITE)

Soil c φ
Pure clay (UU test) cu 0
Dry sand 0 φ
Saturated sand 0 φ
Cohesionless soil 0 φ

🔹 2. TYPES OF SHEAR TESTS (VERY IMPORTANT)

🔸 Direct Shear Test

✔ Simple & quick
✔ Failure plane is pre-determined
❌ Non-uniform stress distribution

🔸 Triaxial Compression Test (MOST RELIABLE)

Test Drainage Parameters
UU No drainage cu
CU Drainage during consolidation c′, φ′
CD Full drainage c′, φ′

🔸 Unconfined Compression Test (UCT)

🔹 3. IMPORTANT MOHR CIRCLE RESULTS (DIRECT QUESTIONS)

🔸 Principal Stresses

🔸 Shear Strength at Failure

🔸 Normal Stress on Failure Plane

🔸 Angle of Failure Plane

(measured from major principal plane)

🔹 4. IMPORTANT FORMULAS (EXAM READY)

🔸 Factor of Safety (Shear)

🔸 Shear Strength in Total Stress (Undrained)

🔸 Shear Strength in Effective Stress

🔹 5. IMPORTANT NUMERICAL EXAMPLES (SSC JE LEVEL)

🔢 Example 1 (Direct Mohr–Coulomb)

Given:
c = 20 kN/m²
φ = 30°
σ′ = 100 kN/m²

🔢 Example 2 (Pure Clay – Undrained)

Given:
cu = 50 kN/m²

🔢 Example 3 (UCT)

Given:
Unconfined compressive strength

🔢 Example 4 (Mohr Circle)

σ₁ = 300 kN/m²
σ₃ = 100 kN/m²

🔢 Example 5 (Failure Plane Angle)

φ = 30°

🔹 6. 50 EXAM-LEVEL MCQs

(25 THEORY + 25 NUMERICAL)

🟢 THEORY MCQs (1–25)

Q1. Shear strength of soil depends on:

  1. Total stress
    B. Pore pressure
    C. Effective stress ✅
    D. Void ratio only

Q2. For pure clay under undrained condition:

  1. c = 0, φ ≠ 0
    B. c ≠ 0, φ = 0 ✅
    C. c = 0, φ = 0
    D. c ≠ 0, φ ≠ 0

Q3. Mohr–Coulomb failure envelope is:

  1. Curved
    B. Parabolic
    C. Straight line ✅
    D. Circular

Q4. Which test is most reliable for shear strength?

  1. Direct shear
    B. Vane shear
    C. Triaxial compression ✅
    D. UCT

Q5. In unconfined compression test:

  1. σ₁ = 0
    B. σ₃ = 0 ✅
    C. σ₂ = 0
    D. τ = 0

🟡 NUMERICAL MCQs (26–50)

Q26. c = 25 kN/m², φ = 0°, σ = 80 kN/m²

Shear strength =
A. 25
B. 80
C. 105
D. 25 kN/m² ✅

Q27. φ = 30°. Angle between failure plane and major principal plane is:

  1. 30°
    B. 45°
    C. 60° ✅
    D. 75°

Q28. σ₁ = 200 kN/m², σ₃ = 80 kN/m²

Maximum shear stress =
A. 60
B. 80
C. 120
D. 60 kN/m² ✅

Q29. If pore water pressure increases, shear strength will:

  1. Increase
    B. Decrease ✅
    C. Remain same
    D. Double

Q30. In UU test, shear strength parameter obtained is:

  1. c′
    B. φ′
    C. cu ✅
    D. φ

🔥 EXAM TRICKS & SHORTCUTS

τ = c + σ′tanφ → most repeated formula
Pure clay (UU) → φ = 0
Dry/saturated sand → c = 0
UCT → cu = qu/2
Failure plane angle = 45 + φ/2
Shear strength ↓ when pore pressure ↑

(Q31–Q50 include: failure plane angle traps, UCT numericals, drained vs undrained MCQs, Mohr circle substitutions)

SHEAR STRENGTH OF SOIL – MOHR–COULOMB THEORY

(SSC JE | RRB JE | OSSC JE)

Focused exactly on failure-plane angle traps, UCT numericals, drained vs undrained concepts, and Mohr-circle substitutions.

🟡 NUMERICAL & CONCEPTUAL MCQs (31–50)

Q31. Angle of internal friction of soil is 40°.

Angle between failure plane and major principal plane is:
A. 45°
B. 55°
C. 60°
D. 65° ✅

Solution:

Q32. Angle between failure plane and minor principal plane is:

  1. B.
    C. ✅
    D. φ

Q33. In an unconfined compression test, if

,
the undrained cohesion is:
A. 45 kN/m²
B. 60 kN/m²
C. 90 kN/m² ✅
D. 180 kN/m²

Solution:

Q34. In UCT, the angle of internal friction (φ) for saturated clay is assumed as:

  1. 0° ✅
    B. 15°
    C. 30°
    D. 45°

Q35. Major principal stress in UCT is equal to:

  1. qu
    B. qu / 2
    C. qu + σ₃
    D. qu (since σ₃ = 0) ✅

Q36. A triaxial test in which pore pressure is not measured and no drainage is allowed is:

  1. CD test
    B. CU test
    C. UU test ✅
    D. Direct shear test

Q37. Parameters obtained from CD triaxial test are:

  1. cu
    B. c, φ (total stress)
    C. c′, φ′ (effective stress) ✅
    D. φ = 0

Q38. In drained condition, shear strength depends on:

  1. Total stress
    B. Effective stress ✅
    C. Pore pressure
    D. Water content only

Q39. Increase in pore water pressure causes shear strength to:

  1. Increase
    B. Remain same
    C. Decrease ✅
    D. Double

Q40. For a cohesionless soil, Mohr–Coulomb equation reduces to:

  1. τ = c
    B. τ = σ
    C. τ = σ tanφ ✅
    D. τ = c + σ

Q41. Given:

σ₁ = 400 kN/m², σ₃ = 200 kN/m²
Maximum shear stress is:
A. 100
B. 150
C. 200
D. 100 kN/m² ✅

Solution:

Q42. Normal stress on the plane of maximum shear is:

  1. σ₁
    B. σ₃
    C. (σ₁ − σ₃)/2
    D. (σ₁ + σ₃)/2 ✅

Q43. In Mohr circle, the radius represents:

  1. Normal stress
    B. Shear stress
    C. Maximum shear stress ✅
    D. Cohesion

Q44. Failure envelope for Mohr–Coulomb criterion is:

  1. Circle
    B. Parabola
    C. Straight line touching Mohr circles ✅
    D. Ellipse

Q45. If φ = 0°, soil behaves as:

  1. Sand
    B. Gravel
    C. Pure clay under undrained condition ✅
    D. Over-consolidated clay

Q46. Which soil shows only frictional resistance?

  1. Saturated clay
    B. Organic clay
    C. Dry sand ✅
    D. Soft clay

Q47. Shear strength mobilized at failure plane is maximum when:

  1. σ is maximum
    B. τ is maximum
    C. Mohr circle touches failure envelope ✅
    D. σ₃ = 0

Q48. Increase in normal stress on a soil sample causes shear strength to:

  1. Decrease
    B. Remain constant
    C. Increase for φ ≠ 0 ✅
    D. Become zero

Q49. In UU test on saturated clay, increase in confining pressure will:

  1. Increase cu
    B. Decrease cu
    C. Not change cu significantly ✅
    D. Make φ non-zero

Q50. Which statement is TRUE?

  1. Drained test gives cu
    B. Undrained test gives c′ and φ′
    C. UCT is a special case of triaxial test with σ₃ = 0 ✅
    D. Failure plane angle is independent of φ

🔥 FINAL EXAM RECAP (MUST REMEMBER)

τ = c + σ′tanφ → core formula
Failure plane angle = 45° + φ/2
UCT → cu = qu / 2, φ = 0
UU → total stress, CD/CU → effective stress
Mohr circle touches envelope at failure

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